Multiplying and dividing Rational Expressions

I dont seem to understand this, can someone please go step by step on these please?

3x^2 + xy^3/y^3 times 2xy+8y/4x + x^2

and

3C^2 + 24C/C^2 - 2C +1 Divided by c^2 + 9c + 8/9c-9

(3x^(2)+(xy^(3))/(y^(3)))*(2xy+(8y)/(4)*x+x^(2))

Remove the common factors that were cancelled out.
(3x^(2)+x)*(2xy+(8y)/(4)*x+x^(2))

Reduce the expression (8y)/(4) by removing a factor of 4 from the numerator and denominator.
(3x^(2)+x)*(2xy+2y*x+x^(2))

Multiply 2y by x to get 2xy.
(3x^(2)+x)*(2xy+2xy+x^(2))

Since 2xy and 2xy are like terms, add 2xy to 2xy to get 4xy.
(3x^(2)+x)*(4xy+x^(2))

Multiply each term in the first group by each term in the second group using the FOIL method. FOIL stands for First Outer Inner Last, and is a method of multiplying two binomials. First, multiply the first two terms in each binomial group. Next, multiply the outer terms in each group, followed by the inner terms. Finally, multiply the last two terms in each group.
(3x^(2)*4xy+3x^(2)*x^(2)+x*4xy+x*x^(2))

Simplify the FOIL expression by multiplying and combining all like terms.
(12x^(3)y+3x^(4)+4x^(2)y+x^(3))

Remove the parentheses around the expression 12x^(3)y+3x^(4)+4x^(2)y+x^(3).
12x^(3)y+3x^(4)+4x^(2)y+x^(3)


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(3c^(2)+(24c)/(c^(2))-2c+1)/(c^(2)+9c+(8)/(9)*c-9)

Reduce the expression (24c)/(c^(2)) by removing a factor of c from the numerator and denominator.
(3c^(2)+(24)/(c)-2c+1)/(c^(2)+9c+(8)/(9)*c-9)

To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is c. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
(3c^(2)*(c)/(c)-2c*(c)/(c)+(24)/(c)+1*(c)/(c))/(c^(2)+9c+(8)/(9)*c-9)

Complete the multiplication to produce a denominator of c in each expression.
((3c^(3))/(c)-(2c^(2))/(c)+(24)/(c)+(c)/(c))/(c^(2)+9c+(8)/(9)*c-9)

Combine the numerators of all expressions that have common denominators.
((3c^(3)-2c^(2)+24+c)/(c))/(c^(2)+9c+(8)/(9)*c-9)

Reorder the polynomial 3c^(3)-2c^(2)+24+c alphabetically from left to right, starting with the highest order term.
((3c^(3)-2c^(2)+c+24)/(c))/(c^(2)+9c+(8)/(9)*c-9)

Multiply (8)/(9) by c to get (8c)/(9).
((3c^(3)-2c^(2)+c+24)/(c))/(c^(2)+9c+(8c)/(9)-9)

To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 9. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
((3c^(3)-2c^(2)+c+24)/(c))/(c^(2)+9c*(9)/(9)+(8c)/(9)-9)

Complete the multiplication to produce a denominator of 9 in each expression.
((3c^(3)-2c^(2)+c+24)/(c))/(c^(2)+(81c)/(9)+(8c)/(9)-9)

Combine the numerators of all expressions that have common denominators.
((3c^(3)-2c^(2)+c+24)/(c))/(c^(2)+(81c+8c)/(9)-9)

Combine all like terms in the numerator.
((3c^(3)-2c^(2)+c+24)/(c))/(c^(2)+(89c)/(9)-9)

To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is 9. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
(1)/(c^(2)*(9)/(9)+(89c)/(9)-9*(9)/(9))*(3c^(3)-2c^(2)+c+24)/(c)

Complete the multiplication to produce a denominator of 9 in each expression.
(1)/((9c^(2))/(9)+(89c)/(9)-(81)/(9))*(3c^(3)-2c^(2)+c+24)/(c)

Combine the numerators of all expressions that have common denominators.
(1)/((9c^(2)+89c-81)/(9))*(3c^(3)-2c^(2)+c+24)/(c)

Any number raised to the 1st power is the number.
(1)/(((1)/(9))(9c^(2)+89c-81))*(3c^(3)-2c^(2)+c+24)/(c)

Multiply the rational expressions to get (9)/((9c^(2)+89c-81)).
(9)/(9c^(2)+89c-81)*(3c^(3)-2c^(2)+c+24)/(c)

Multiply the rational expressions to get (9(3c^(3)-2c^(2)+c+24))/(c(9c^(2)+89c-81)).
(9(3c^(3)-2c^(2)+c+24))/(c(9c^(2)+89c-81))